Yet another 10B question

[ILL]

Okay this is really frustrating me now, as every other cipher before this had been far easier (I get that that’s the point) but I have been stuck on this for what feels so long now and nothing I do comes out with legible stuff. Around challenge 8 I had programmed on python a code that splits the cipher text provided into a chain of those characters, what it would do after is read each sequence and give it a number (I would try different chain lengths until I had under 27/26 repeated patterns. This worked for the previously uncoded 6 needle telegram, but since day one I knew that a chain length of 3 (as seen in the latest hint) would give 27 unique characters.

My problem is with the new hint groups of 3 characters such as \\\ ||| and /// would not code for anything in this new needle telegraph revealed in Sunday’s hint.

Am I over complicating it, as I always do, or is it seriously as simple as sequences encoding for the same letter of 6, because that can’t be right, right?

-ILL

[someone]

I also have tried many things for days and it this point I’m stuck. Today’s clue is a sequence of numbers for each character and I think I could decrypt the message if only I knew where those numbers came from. Please anybody who has solved part B give even the slightest hint for us.

I think the hint tells you what to do! Harry

[someone]

It says to count. Me: hmm, 1, 2, 3, 4, 5, 6 … 21168 – that took a while and i didn’t notice a thing. I just don’t understand where/how to find the number sequence in case files, what its significance is or why it is going up just with different amount of numbers for each step.

[T-T]

maybe how and what to count

[ILL]

Okay so to develop on this, today’s (Tuesday) hint implies that the groups of the characters surpasses sequences of three, instead, is all about storing the previous data. But I still have an issue, it suggests initially that the data goes up to 7056 of each character and that there is 21000 so vertical groups of three (which would encode for far too many characters!). Personally, I believe I am interpreting the hint wrong, and that there might be a modulus after to cut the number 7056 down to one digit or so or the data is interpreted, as matrixes are, in a 3×3.

I really don’t know anymore, but I am glad that the creators have give until the 27th for the next point reduction. However, I am a bit disappointed with myself for doing incredibly well so far, only to be completely stumped by this final challenge part B.

Have a Happy Holidays!

-ILL

[Olive-Tree3]

Hey everyone,

Is it possible to understand all but one of the case files and still not have a clue what to do? That’s my current state right now; PLEASE help, me and our team are really struggling! ALso, do we have to split the text into groups of three? I’ve done that and want to know if I’m on the right track or not! Thank you.

Splitting the text the right way is definitely the right thing to do. Of course you need to work out what way that is! Harry

[Olive-Tree3]

Also @someone it would be useful for you to count more carefully, and more closely… hopefully Harry will allow that hint. But just a word: 10.5 doesn’t help AT ALL (in fact it seems completely unrelated) so if you don’t get my hint it doesn’t matter much.

Several people have posted that 10.5 doesn’t help, but if you do what it tells you to do and look very carefully at what you get, then it should be really quite helpful! Harry

[Olive-Tree3]

WAIT so Harry how do I find out how to split the text? Also does it include adding and subtracting symbols, because I know people are saying that but I don’t think it’s the best way to do it… it would also take a LOT of time/python coding which I have no idea how to do..
PLEASE help

do I need to split the text into groups larger than 3? I don’t think this is likely but just to confirm?

thanks

You definitely need to split the text up into chunks longer than three characters to start the decryption! Harry

[someone]

@Olive-Tree3 try frequency analysis on very very small chunks(less than 50) and find the smallest one that has the same amount of each character – i then believe you must reorder them in a correct way that it correctly orders the entire cipher.

[someone]

I have just discovered what case files 10.5 is, but was wondering what it actually helps with. Any tips?

[Author]

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