Maths
Tagged: #Question
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5th December 2024 at 8:14 pm #98774Kingswinford-Warriors-AlumniParticipant
#98720
Sorry! I forgot that the grave character (i.e. what 1 gets ROT47-ed to) would cause some formatting issues. [So some of the 1s have become random newlines.] I’ll try to post the hints in a different way at some point…#98721
Problem 1 – Kim wants to use as little fencing as possible. (I should have clarified that in the problem statement!)(General)
Harry, it seems like this topic has been shifted to the second forum page for a few days now, and so it’s probable that no-one else is seeing these posts! Can you change this in some way? Thanks.6th December 2024 at 2:45 pm #98792Kingswinford-Warriors-AlumniParticipant[General message: Sorry for the abundance of posts recently!]
#98720 (Hints for #98066)
Let’s try again! I have reverted to a ROT13 cipher (i.e. Caesar shift of 13), combined with a ROT5 (i.e. Caesar shift of 5 on the digits only) to scramble the numbers slightly. Note that this does not change things like symbols or brackets, so some of the structure of the hints has been retained.
You view these hints at your own risk. (Disclaimer)
Everything fine? Great. On with the hints!
HINT 0 (solutions)
Gur bayl inyhr bs (n,o,c) gung jbexf vf (6,6,7).
HINT 1 (FLT)
Srezng'f Yvggyr Gurberz fgngrf gung, sbe nal cevzr c naq vagrtre x pbcevzr gb c, x^(c-6) unf erznvaqre 6 ba qvivqvat ol c. (Be x^(c-6)=6 zbq c.) Zber hfrshyyl sbe guvf ceboyrz, vg nyfb zrnaf gung sbe nal cevzr c naq NAL vagrtre x, x^c naq x unir gur fnzr erznvaqre ba qvivqvat ol c. Guvf zrnaf gung jr znl ercynpr, fnl, n^c ol n va gur ceboyrz naq fgvyy cerfreir gur erznvaqre ba qvivqvat ol c...
HINT 2 (first steps)
Nf uvagrq ng va Uvag 6, hfr SYG gb zbqvsl gur yrsg-unaq fvqr bs gur rkcerffvba, juvyfg cerfreivat vgf erznvaqre ba qvivqvat ol c. (Gung vf, pbafvqre obgu fvqrf zbq c.) Qrqhpr gung n+o=5 (zbq c), be gung c qvivqrf n+o.
HINT 3 (bounds on a,b,a+b)
Uvag 7 fgngrq gung c qvivqrf n+o. Vs c=7 gura jr unir n^7+o^7=7, juvpu vf rnfl gb purpx, fb nffhzr c>7. Abgr gung c vf bqq. Yrg a=(c+6)/7. Jevgr a^c naq c! nf sbyybjf (ivrj va n zbabfcnprq sbag): a^c = [a*a] * [a* a ] * ... * [ a * a ] * a c! = [6*c] * [7*(c-6)] * ... * [(a-6)*(a+6)] * a Cebir gung rnpu bs gur oenpxrgf sbe a^c ner ynetre guna gubfr sbe c!. Urapr, fvapr n^c < c! < a^c, qrqhpr gung n<=(a-6). Fvzvyneyl fubj o<=(a-6), naq urapr fubj gung n+o<c.
HINT 4 (final steps)
(V nz nffhzvat c>7 urer, nf fgngrq va Uvag 8...) Uvag 7 fnvq gung c qvivqrf n+o. Uvag 8 fnvq gung n+o<c. n naq o ner cbfvgvir, fb jr nyfb unir n+o>5. Qrevir n pbagenqvpgvba.
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