Reply To: Maths

Ive had it for a while but didnt upload because i might be missing a solution. Currently I have:

a^p + b^p = p!
a^p + b^p = p(p-1)!

Therefore,
(a^p – a + b^p – b) / ((p-1)!) = p
a^p + b^p = a^p – a + b^p – b
0 = -a -b
so, -a=b and -b=a therefore a=0,b=0 BUT as a,b ^p, even powers ignore the negative effect so p=2
a^2 + b^2 = 2 which gives:
a=1, b=1, p=2

This is my only solution so far, nice problem though