Reply To: Programming

@BytesInBits

Whoops, I didn’t see that. After adding a counter to my code, it appears there are 4563 sets.

Here’s my solution for question 1, as it appears Harry has forgotten about it.
All in one line, because why not? (I swear my code normally isn’t as garbage as Q1 and Q3…)

print(next(filter(lambda x: all(x % (4, 5, 7, 11, 17)[i] == (3, 1, 2, 2, 12)[i] for i in range(5)), range(5000, 50000))))
Output: 29031